/* program to compute bearings cost, multiple times
  Sept 22, 1997
  CS1711A Class*/

#include <iostream.h>

int main()
{ const double PI=3.14159;
  const double HI_CARBON_PRICE = 1.35;
  const double LO_CARBON_PRICE = 1.00;

  int number_bearings;
  double radius, total_volume, volume_of_one;
  char carbon,continu;

  do {  // while continu = Y
	cout << "Input a decimal number for the radius\n";
	cin >> radius;
	cout << "How many bearings?\n";
	cin >> number_bearings;
	cout << "Input carbon: high (h) or low (l)\n";
	cin >> carbon;

	volume_of_one = 4.0/3.0*PI*pow(radius,3.0);
	total_volume = number_bearings* volume_of_one;


	if (carbon=='h'|| carbon=='l') /*valid inputs*/
	 { cout << "The total volume required for " << number_bearings;
	  cout << " bearings of radius " << radius << " is ";
	  cout << total_volume;

	  // format for 2 decimal output
	  cout.setf(ios::fixed);
	  cout.setf(ios::showpoint);
	  cout.precision(2);

	 {if(carbon=='h')
		cout << endl << "Total cost is $ " << total_volume*HI_CARBON_PRICE;
	  else
		 cout << endl << "Total cost is $ " << total_volume*LO_CARBON_PRICE;}}
	else  /*traps bad input*/
		 {cout << endl << "Invalid input " << carbon;
		  cout << endl << "Input value must be 'h' or 'l'";}
	cout << endl;
	cout << "Input 'Y' to continue, 'N' otherwise";
	cin >> continu;

  }
  while (continu=='Y');
  return 0;

}