Date: Sat, 12 Aug 1995 23:53:41 -0300 (ADT) From: categories To: categories Subject: separate continuity Date: Fri, 4 Aug 95 15:32:33 EDT From: Michael Barr Does anyone know anything about topological spaces for which the topological spaces for which the topology of separate continuity on their square coincides with the product topology? No non-discrete T_1 topology is possible; any order topology has the property and we have at least one other space and that about exhausts our knowledge of the subject. Michael Date: Tue, 15 Aug 1995 14:05:22 -0300 (ADT) From: categories To: categories Subject: Re: separate continuity Date: Mon, 14 Aug 95 19:58:55 +0200 From: Reinhold Heckmann Concerning the question "Which are the spaces X such that the topology of separate continuity on X x X coincides with the product topology?" I know of the following result: for a T0-space X, the following are equivalent: 1) for every T0-space Y, the topology of separate continuity coincides with the product topology on X x Y, 2) whenever a point x of X is in an open set U of X, there are a finite set F and an open set V of X such that x in V subset up F subset U. Here, up F is { b in X | b is above some a in F in the specialization preorder }. To prove 1 => 2, let Y be the space of open sets of X, where the topology is generated by assuming all neighborhood filters of points of X as open. Every continuous dcpo with its Scott topology satisfies condition (2) with F being a singleton. There are non-continuous dcpo's which also do; called quasi- or multi-continuous by some authors. With T1, up F = F holds. Thus, the only T1-spaces satisfying (2) are the discrete spaces. The above condition (2) probably is only sufficient, but not necessary for the special case of X x X. Hence, this is only a partial answer to the original question. Reinhold Heckmann Universitaet des Saarlandes